#include "d:\Practice Programs\Puzzle Feuer\Puzzles\defs.h"

// win 98 is 32 bit platform.  So int is 32 bit.


/****
SEE BOOK FOR DIAGRAM.   MAKES THIS VERY CLEAR. 
*****/


int  a[] = { 0, 1, 2, 3, 4 };
int *p[] = { a, a+1, a+2, a+3, a+4 };
int **pp = p;

// a[] is an int array.
// p[] is an array of int addresses
// pp is a double pointer to an array of int pointers 
// 'pp' points to 'p' which points to a[0]

main()
{
	// '*p' de-references the pointer 'p' to show what the pointer points to.
	PRINT2(d,a,*a);		    //a = 4218928	*a = 0	
	PRINT3(d,p,*p,**p);		//p = 4218952	*p = 4218928	**p = 0	
	PRINT3(d,pp,*pp,**pp);	//pp = 4218952	*pp = 4218928	**pp = 0	
	NL;						//'pp' has ad of 'p', '*pp' is what 'p' holds, the ad of'a'
							//'**pp' is a double de-references of 'pp' 
							//which give what 'a' holds. 'a' == 'a[0]'
/*
pp = p, *pp = a, **pp = a[0]
*/

	pp++; //now pp double ref points to a[1] = 1, p points to a=a[0]=0,  So 1-0=1 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 1	*pp-a = 1	**pp = 1	
	*pp++; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 2	*pp-a = 2	**pp = 2	
	*++pp; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 3	*pp-a = 3	**pp = 3	
	++*pp; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 3	*pp-a = 4	**pp = 4	
	NL;

	pp=p; //  pp to 
	**pp++; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 1	*pp-a = 1	**pp = 1	
	*++*pp; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 1	*pp-a = 2	**pp = 2	
	++**pp; 
	PRINT3(d,pp-p,*pp-a,**pp);	//pp-p = 1	*pp-a = 2	**pp = 3	


}// end main