#include "D:\Practice Programs\Puzzle Feuer\Puzzles\defs.h"


void
main()
{


	double b, d;	
	
	int x, y, z;
	x=16; y=2; z=0;


//Bit Shifting	
	PRINT3(d,x,y,z); 
	z=x<<y;			// must have a resultant.
	PRINT3(d,x,y,z);
x=16; y=2; z=0;
	PRINT3(d,x,y,z);
	z=~x;
	PRINT3(d,x,y,z);

//Logic operators	

x=16; y=2; z=0;
	PRINT3(d,x,y,z); 
	z=x&&y;
	PRINT3(d,x,y,z); 
x=0; y=2; z=1;
	PRINT3(d,x,y,z); 
	z=x&&y;
	PRINT3(d,x,y,z); 

//Type operators

x=0; y=2; z=0;
	PRINT3(d,x,y,z); 
	z=sizeof x;
	PRINT3(d,x,y,z); 
	z=sizeof 2;
	PRINT3(d,x,y,z); 
	z=sizeof "a";
	PRINT3(d,x,y,z); 
	z=sizeof "operators";
	PRINT3(d,x,y,z); 

/*Thpe Hierarchy Chart

  Before a binary arithmetic operator is evaluated, the two operands are converted to the
  type of the higher typed operand.
	
long double <- double <- float <- unsigned long <- long <- unsigned int (<- unsigned short) <- int <- char, short
		
Here y is converted to type bouble.   This convertion does not effect the resultant.
If int = double + int; the resultant int will not be converted.
*/

b = 0;
d = 55.55;
b = y + d;
PRINT1(f,b);

}